I didnt know where to post it so just posted here, if it belongs to some other section mod's please help me.
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I didnt know where to post it so just posted here, if it belongs to some other section mod's please help me.
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That's repost![]()
Good one![]()
Good thread.![]()
Check this out...
Try to multiply 142857 with 2,3,4,5,6.. Can you tell what's so special about results?
the same numbers will come in result also but in jumbled form
I searched for it after the above post. http://en.wikipedia.org/wiki/142857_(number)
142,857 is the six repeating digits of 1/7, 0.142857, and is the best-known cyclic number in base 10. If you multiply the number by 2, 3, 4, 5, or 6, the answer will be a cyclic permutation of itself.
Last edited by gothic_coder; 05-30-09 at 02:11 PM. Reason: Automerged Doublepost
Assumption-
Let a=b
multiplying both sides by a,
a^2 = ab
Subtracting b^2 from both sides
(a^2) - (b^2) = ab - (b^2)
Now expanding above
(a-b)*(a+b) = b*(a-b)
canceling (a-b) on both sides we get,
(a+b) = b
hence if a=b=1
then we get (1+1)=1
ergo 2=1!!!!
The above proof is mathematically not right...
The flaw may be spotted.... :12:
^ right ofcourse!!![]()
Tukka lag gaya...
(p.s dont be serious @ my non serious posts)
how can i!! i dint understand what you said![]()
good thing I love math! the computation is just awesome, I wonder how long did it take to finish all those computation.![]()
This is one of the best thread I have seen.
Great Work Starter.
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